game --- four's four

last SG · 2006-02-14T23:11:47+00:00

no i mean i start from 0 den the next 1 continue from 1,2,3 etc... den see until which no, we cant come up with the solution

finoq SG

2=(4/4)+(4/4)
7=4+4-4/4
9=4+4+4/4

ndmmxiaomayi SG

4 = 4*4/4 --> This one don't know can or not or rules still applies?

If yes

4 = sqrt 4 + (4/4 x 4)

The next one before I sleep. Happy playing Wink

5 = sqrt 4 + 4/4 + sqrt 4

RaTtY81 SG

4^2 – 4 – 4 – 4 = 4

RaTtY81 SG

5 = ({4×4}+4)/4

finoq SG

9=4+4+4÷4

Following BODMAS rule

finoq SG

11 = (Factorial 4) ÷ (Squareroot 4) - 4 ÷ 4

BTW can use Factorial?

finoq SG

Assuming Factorial (!) can be used...

13 = 4! ÷ Sqrt4 +4 ÷ Sqrt4

15 = 4×4-4÷4

16 = 4+4+4+4

17 = 4×4+4÷4

19 = 4! -4-4÷4

21 = 4! -4+4÷4

27 = 4! + Sqrt4 +4÷4

29 = 4! + 4 + 4 ÷ 4

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