Object-Oriented Programming

last SG · 2007-09-28T00:01:06+00:00

That piece of code is not Java, although concepts are the same.

Xcert SG

anyone knows how can I print out the name of the manager in the last line.

Employee is the base class,manager is the derived class.

manager.name is obviously not correct. Crying or Very sad

caleb_chiang SG

what language is this? Rolling Eyes

eagle SG

C++
as seen from cout

long time since I have touched it, so I cannot help. Sry

caleb_chiang SG

Wah~ me like 10 yrs never touch C liao... no wonder can't recognise... Laughing

ndmmxiaomayi SG

Not trained in this language... I think Fatum may know. Smile

eagle SG

have u tried

cout<<"nOffice of "<<<" is Office "<

because I think derived class means it is still something within the manager class

LatecomerX SG

I guess you can try declaring the employee.name as a public variable instead, so that it can be accessed by its derived classes. But anyway, I'm not that good in OOP, so please correct me if I'm wrong.

Hence, the code should be:

manyu882 SG

lol. i got A for that module. but then i forget everything liao lol.

thoreldan SG

havent read thru the code...

but it's bad to declare name as public

the standard way is to make a public assessor to access the name instead

thoreldan SG

u can do this

public:

char* PrintName();

-------------
inside just return the name lor

LatecomerX SG

Hmm let me learn something here.

So you mean something like, under "public:" of the employee class, you have a method named GetName() which basically returns the private "name" property?

PS:
Argh you answered my question before I posted it. lol.
So what's so bad about making a property/var public?

thoreldan SG

try it...see if it works

Xcert SG

error C2248: 'name' : cannot access private member declared in class 'employee'

Xcert SG

yup it works.thanks.

care to explain more on ur method of accessing a private member variable of a private class?

ndmmxiaomayi SG

Your variable "name" in the employee class is private; it's protected. You can't access it this way. Will need to declare it as public if you want to access it.

croco2006 SG

mi o level nia

Xcert SG

yup.LatecomerX's method also works...but my problem is that "name" must be declared as private(a requirement) so I cant suka suka change it to public.

Xcert SG

nowadays primary sch learn how to program robots. Laughing Mr. Green

ndmmxiaomayi SG

Private can only access with private... as far as I know. LateComerX's method will work as well, because it's within the same class. It's not like another class is trying to access the private class.

eagle's method is actually utilizing another class to access the employee class, so it runs foul, producing an error. The error is quite easy to understand:

'name' : cannot access private member declared in class 'employee'

eagle SG

Yep, use LateComerX's method.