Hi
(i) If we rearrange, we get
(10p + d) / (10d + q) = p/q
Comparing, we get
p = 1, q = 4 and d = 6
(ii) Expanding the first equation, we get
10pq + dq = 10 pd + pq
9pq + dq - 10pd = 0
I am unsure of the syllabus, of the level, at which this
question is pitched at.
So, I would do a trial and error method to solve, which may or may
not be in syllabus given the lack of information
p = 1 gives us an answer already
The other 3 cases (apart from p, q, and d the same numbers, and
non-zeros)
are
p = 1, q = 5 and d = 9
p = 2, q = 5 and d = 6
p = 4, q = 8 and d = 9