2013/P1/11
for the equation of the auto ionisation of water, why is it that
the equilibrium lies(when no change is made to the eqm) to the
left? is it becos L.H.S of the eqn has 1 mol, R.H.S has 2 mol? (but
a system always tends towards max entropy,one factor is increased
no. of particles. so why would eqm lies to the left?)
is it correct that H2O《》H+ + OH- ΔH=+58kj/mol , is in a state of
dynamic eqm but the equilibrium position lies to the left?
i thought that , under the right conditions, and also in a
closed system, a reversible reaction will reach a state of dynamic
equilibrium.
is it right that given enough time and in a closed system, All
reversible reactions will reach dynamic equilibrium, and All has a
equilibrium position either lying left,or right side of the
equilibrium ah ?
Yes, correct. The position of equilibrium lies to the LHS (ie. Kc
value less than 1), because H2O is more thermodynamically stable
compared to H+ and OH-.