page 148 cs toh advanced guide
example 6, at bottom of page
PCl5 (g)《》PCl3(g) +Cl2 (g)
yes i understand cstoh's explanation, and understand less
PCl5(g) would dissociate
noted that Kp is not affected by changes in pressure (because
partial pressure or in other cases, concentration, the
partialP/conc , of both reactants and products increases/decreases
by same amount right? )
but i thought of what I've learnt ,read , and done questions
before,
when P decrease, eqm position shift left as predicted by LCP,
wouldn't conc PCl5 increase?
See see see?!? Again, I bet your school didn't teach you properly.
This is one of the all too common misconceptions suffered by
Singapore JC students.
When pressure is changed (by changing the volume of the
container), the molarities and partial pressures of the reactants
and products change, hence because Kc & Kp doesn't change
(since temperature doesn't change), and Qc & Qp now changes,
hence position of equilibrium shifts, so as to allow Qc & Qp to
equalize with Kc & Kp, to re-establish equilibrium.
In other words, position of equilibrium shifts BECAUSE Kc &
Kp doesn't change. Geddit? U think ur school mates truly understand
this concept / topic, when even u urself are confused?
