what's the oxidation state of N in
nitrobenzene?
some from internet says its +3 ,some say
it's +5
help ultima
check my drawing of nitrobenzene pls
ultima, thanks
https://www.dropbox.com/s/ai69tw8ehxq6701/20160925_205912-1.jpg?dl=0
update : i got +3. is it correct?
what about the oxidation state of N in
the resonance hybrid?
Your drawing and (thus) OS are wrong.
Either you show formal charges and don't show dative bond (the
BedokFunland JC way used in University level), or you show dative
bond and don't show formal charges (the Singapore JC way because
most JCs don't teach H2 Chem students about formal charges, only H3
Chem, Olympiad Chem and BedokFunland JC students have this
educational privilege).
Redraw your nitrobenzene correctly, using both alternative
ways.
Draw at least the first couple of resonance contributors (ie.
benzene ring pi electrons delocalizing into the NO2 group), then
you'll see the answer clearer for yourself.
I won't spoonfeed you the final answer for OS : draw out the
resonance contributors correctly, then work out the OS of N
yourself (hint : if the OS of N differs in different resonance
contributors, you can only conclude the OS of N in the resonance
hybrid is somewhere in between the different OS obtained for
individual contributors).