For a reaction whose rate= k
[CH3CHO][CH3OH][H+]
exp
[CH3CHO]
[CH3OH]
[H+]
relative rate
1 0.20
0.10 0.05
1.00
2 0.25
0.10 0.05
1.25
3 0.25
0.16 0.05
2.00
Calculate the
relative rate of reaction for a mixture in which the starting
concentrations of all three reactants are
0.20moldm–3
.
Do we hve to use the rate expression for this ?
Since all 3 reactants are 1st order (as per the rate eqn), hence
based on exp 1, the new rate of reaction will be : 1.00 x
(0.20/0.20)^1 x (0.20/0.10)^1 x (0.20/0.05)^1 = 8.00