To answer Q2
Just to add,(though it's A level requirement) I am quite
uncomfortable mentioning enthalpy change of combustion (as the
definition of enthalpy change of combustion is the energy change
when 1 mole of an reactant is completely combusted in excess oxygen
[if we mention standard enthalpy change of combustion it's at
standard conditions of 298K, 1 atm])
For isomers (since TS mentioned same molecular formulae, I will
assume it's referring to structural isomers - rather than geometric
isomers), there can be a case when enthalpy change of combustion
maybe different:
E.g.
C3H6O2 can refer to either ethylmethanoate (CH3CH2OCOH) or
propanoic acid (CH3CH2COOH). When 1 mole of either compound
completely combusted in oxygen, there will be 3 mole of CO2 and 3
mole of H2O
Equations will be as follows
CH3CH2OCOH + 7/2O2 --> 3 CO2 + 3 H2O (equation
A)
CH3CH2COOH + 7/2O2 --> 3 CO2 + 3
H2O (equation B)
Using Bond energies to derive enthalpy changes of equation A
& B
Enthalpy change of equation A is
= bond energy of reactants - bond energy of products
= [6 C-H + 1 C=C + 2 C - O + 1 C = O + 7/2 O = O] - [6 C = O + 6
O - H]
= 6006 - 7200
= -1194KJ/mol
Enthalpy change of equation B is
= bond
energy of reactants - bond energy of products
= [5 C-H + 2 C-C + 1 C
- O + 1 C = O + 1 O - H + 7/2 O = O] - [6 C = O + 6 O - H]
= 6064 - 7200
= -1136 KJ/mol
Hence, enthalpy change
of combustion of ethylmethanoate is higher than enthalpy change of
combustion of propanoic acid (theorectical - need to be verified by
bomb calorimetric results / experimental readings)
In conclusion, enthalpy
change of combustion may be different for structural isomers BUT
for geometric isomer do refer to UltimaOnline answer
NOTE: The above is A
level Chemistry already, it will be very out of syllabus for O
level
P.S: UltimaOnline, if
there are errors in my explanation above do point it out, thanks :)
Too long never touch Chemistry cause in NS ...