The correct way of determining orbital hybridization, is by
looking at the electron geometry (and has nothing to do with sigma
vs pi, single vs double vs triple bonds, as is often erroneously
taught in schools).
For instance, the N atom is NH3 has 1 lone pair and 3 bond pairs,
hence electron geometry is tetrahedral, while molecular geometry is
trigonal pyramidal.
In determining orbital hybridization, we focus on the electron
geometry.
Since the electron geometry about the N atom in NH3 is tetrahedral,
the orbital hybridization is sp3.
sp = s + p = 2 electron charge clouds = linear.
sp2 = s + p + p = 3 electron charge clouds = trigonal planar.
sp3 = s + p + p + p = 4 electron charge clouds = tetrahedral.
sp3d = s + p + p + p + d = 5 electron charge clouds = trigonal
bipyramidal.
sp3d2 = s + p + p + p + d + d = 6 electron charge clouds =
octahedral.