I totally get the shape of molecules. Anw, now, i 'm
struggling with Electrochemistry. I confused about this question. I
'm wrong or the solution wrong?
In acidic solutionn, Mn04- ions oxidise Cl- ions to Cl2. The
value of Eo for the reaction is 0.16V. They asks several things but
i think we don't need to care about it.
There are 2 equation of this excercise:
MnO4- +8H+ +5e- => Mn2+ +4H20 Eo= 1.52
V
Cl2 +2e-
=> 2Cl-
Eo = 1.36 V
1. If Mn04 oxidise Cl- to Cl2. I think it must
be reduce or are oxidised.
2. The right equation must be opposite. It must
be:
2Cl- => Cl2 +2e Eo= -1.36
3. In the end, Eo of the whole must be :
=1.52 - - 1.36.
Some one help me plz
Under standard conditions,
Reduction potential of MnO4- to Mn2+ is +1.52V
Oxidation potential of Cl- to Cl2 is -1.36V
Cell potential = [email protected] + [email protected] = (+1.52) + (-1.36) = +0.16V