amount of actual work done by the box up the vertical height is
mgh.
That will be 70N*0.03m=0.21J (Since mg = weight)
Amount of work done by the force pushing up the inclined plane
(slanted) is 0.05m*50N=0.25J
(0.05m is the slanted height derived from pythagorian
triplets)
input work done : output work done
0.25 : 0.21
Ans: 25:21
