Tins A, B and C each contained some coffee
powder. Mr Lim transferred 1/8 of the coffee powder from Tin A to
Tin B, then scooped 1/8 of the coffee powder from tin B into tin C
and finally transferred 1/8 of the coffee powder from tin c to tin
a. Now there are 49g of coffee powder in each tin. How much coffee
powder was there in each tin at first?
working backwards
tin C - 49g (since trf 1/8 out, now 7/8 = 49)
7/8 = 49
1/8 = 7
8/8 = 56g (after receiving from B)
tin A - 49g (after receiving 7g from C)
before receive from C = 42g (which is after giving 1/8 to B)
7/8 = 42
1/8 = 6
8/8 = 48g (before giving to B)
tin B received 6g from A
then give 7g to C
49 + 7 - 6 = 50g
A = 48g
B = 50g
C = 49g
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Mabel had a total of 128 pieces of $5 notes and
$10 notes in her handbag. After she spent 2/7 of her $5 notes and
3/5 of her $10 notes, she had twice as many $10 notes as $5 notes
left.
How many $5notes did Mabel spend?
How much did she spend altogether?
using ratio,
$5
sp : $5 left
2 : 5
$10
sp : $10 left
3 : 2
make
$109 left 2 times of $5 left
(10 u is twice of 5u)
$10
sp: $10 left
15 : 10
2 +
5 + 15 + 10 = 32u
32u = 128 pcs
1u = 4pcs
$5sp = 2u x 4 = $40
$10sp = 15u x 4 = $600
total sp = $640