Can anyone help me with this math question ?

[QUOTE]

John is at town A , moving towards town B at 100M/Min

Mark is at town B , moving towards town A at 80M/min

Dick is at town B , moving towards town A at 75M/Min[

When John and Dick meet while moving toward town A and B , Mark is 6M ahead of them.

John & Dick

------------------------------------V----^---------------

Mark [6M ahead of them]

What is the distance between both towns.

[/QUOTE]

In every hour, the distance between Dick and Mark is increased by 80M-75M=5M

In order to create a 6M difference in distance, they have traveled 6 / 5= 1.2hours. This is also the time taken for John and Dick to meet.

Therefore distance between A and B = 100 x 1.2 + 75 x 1.2 = 210M

Note: its speed is in mins...

change all the hours to minutes.