70cm^3 of a mixture of methane and ethene were exploded in
200cm^3 of oxygen. The volume of the residual gases was found to be
130cm^3. On being shaken with sodium hydroxide, the final volume
was found to be 35cm^3. What is the composition of the
mixture?
A: Volume of methane : 20cm^3 | Volume of ethene : 50cm^3
B: Volume of methane : 35cm^3 | Volume of ethene : 35cm^3
C: Volume of methane : 45cm^3 | Volume of ethene : 25cm^3
D: Volume of methane : 50cm^3 | Volume of ethene : 20cm^3
Can someone explain to me on how to do this question?
Let x cm3 be the volume of methane, and (700-x)cm3 be the volume
of ethene. Based on stoichiometry of the balanced combustion
equations for both methane and ethene (separate equations!), you
can work out the volume of CO2(g) generated, in terms of x. Equate
this volume (in terms of x) with (130 - 35), and solve for x.