1) In O level syllabus, i do not think there is any difference,
but the OH- group in NaOH could be dissociated but the OH group in
hydroxyl cannot, and reactions also differ, OH- in NaOH is for
neutralization and alcohols are weak acids (utima correct me if i
am wrong) and can serve as a group involved in orgainic reactions
(eg esterfication)
2) pH
3) (a) is for alkane and alkene, (b) Cannot observe change,
unless entalpy change is measured, ehthalpy change for
neutralisation for acid is nearly +57 KJ (not the strong acid value
as acidic group is not fully dissociated - need to break bonds).
(c) Best answer, could see effervensence, (d) Useless
SBS n SMRT's answers are correct.
1) Yes, that's right. The hydroxy / hydroxyl OH group is present in
the form of the hydroxide OH- ion in NaOH(aq), which is
basic (ie. can accept protons to form water) and hence
the solution of NaOH(aq) is alkaline (ie. pH > 7 at room
temperature). The hydroxy / hydroxyl OH group in alcohol is
covalently bonded to the alkyl 'R' group and has no (formal or
ionic) charge, and is neutral, ie. pH = 7 at room
temperature (it is not acidic because the conjugate base RO-
alkoxide ion is not stabilized by being delocalized by resonance
and is in fact destablized by the electron donating by induction
alkyl 'R' group; it is not basic because oxygen is electronegative
and holds the lone pair tightly and hence is not available to
accept a proton, and the conjugate acid is unstable because
electronegative oxygen does not like a positive formal charge).
In conclusion, for 'O' levels the two differences are : the OH
group is sodium hydroxide is negatively charged and is basic; the
OH group is alcohol has no charge and is neutral.
2) Yes, that's correct. Non-metal oxides are covalent oxides and
hence are acidic oxides. Due to the greater electronegativity of
oxygen compared to carbon, the carbon is partially positively
charged and is hence electrophilic. It consequently invites
nucleophilic attack by water molecules, forming carbonic(IV) acid
upon hydrolysis :
CO2(g) + H2O(l) ---> H2CO3(aq) ---> H+(aq) + HCO3-(aq)
The protons (H+ ions) will cause the solution to be acidic and
the pH to decrease below 7 (at room temperature), which can
thusly be detected by the Universal Indicator solution.
In addition, when some species of yeast carry out fermentation (ie.
breakdown of carbohydrates), they may also generate lactic acid,
which can also be detected by the Universal Indicator solution.
http://en.wikipedia.org/wiki/Lactic_acid_fermentation
3) SBS n SMRT's answers are correct. The carbonate(IV) ions
would be protonated by the carboxylic acid, forming the
conjugate acid carbonic(IV) acid, which exists in equilibirum
with, and hence can decompose into CO2(g) and H2O(l). Notice that
carbon dioxide, being a gas, leaves the reaction mixture, pulling
the position of equilibrium over to the right.
2RCOOH(aq) ---> 2H+(aq) + 2RCOO-(aq)
2H+(aq) + CO3 2-(aq) ---> H2CO3(aq) ---> CO2(g) +
H2O(l)
Notice how this reaction (ie. the 2nd equation) is the exact
same reaction as in our discussion on Q2, but in the opposite
direction.