Wireless- SG Haha yup. nvm found the answer need to use this identity. Can show me how to derive this identity?
wee_ws SG Hi, First 2 results are double-angle identities, covered in Additional Maths. As for the 3rd result, consider RHS: 1. numerator = 1 - cos(2u) = 1 - [ 1 - 2(sin u)^2 ] 2. denominator = 1 + cos(2u) =1 + [2(cos u)^2 - 1 ]. Thanks.Cheers, Wen Shih
Terminator Hitman SG hey wee,slowly lookin like what i did in past....from formulas!!!!thats odd.......hmmmm..used to go on questions with answers on 1 whole page in past .
wee_ws SG Hi Wireless, You may read a short article I have written at: http://weews.webs.com/laplacetransforms.htm Hope it'll help to clarify your understanding of the topic. Thanks.Cheers, Wen Shih
Terminator Hitman SG wee,damn...u selling past year tutorials???.....u accept paypal??:)download all worked out model answers too??wished they had the internet in those days......