i chanced upon this question, lim (sin x)/x, as x->0.
the solution used geometry i think, but i didnt really
understand it, and i think it uses 0/0. this got me thinking to
whether 0/0 = 0(where you consider 0 divide by any number = 0) or 1
(where u consider 2 of the same numbers divided together to be 1),
or no definite solution (as proven by expressing the division step
as an inversion of multiplication step, eg, let 0/0 = a, therefore
0 = a x 0, and in this way, a can be any number.).
besides that, can anyone explain to me why lim (sin x)/x, as
x->0 = 1 using the geometry method(it involves the triangle and
an arc with the hypoteneuse being the radius of the arc)? (:
