MATH. DY/DX HELP!

dy/dx in(inx^e) .

help appreciated

Hi,

Do you mean: find dy/dx if y = ln (ln x^e)? Thanks.

Cheers,
Wen Shih

Nope. Just differeniate in(inx^e).

the ans is 1/ x In x.

thanks alot!

Hi,

I believe it's to differentiate ln (ln x). Natural logarithm is written as 'ln'. Thanks.

Cheers,
Wen Shih

but the ans isnt 1/x Inx

Hi,

It's clearer if you write the answer as (1/x) (ln x).

In that case, the question may have been to differentiate (1/2) (ln x)^2.

Recall that d/dx [ (ln x)^n ] = n . (ln x)^(n - 1) . (1/x).

Thanks.

Cheers,
Wen Shih

Thanks !

de original question was correct.

d [ln (ln x^e)] / dx

= d [ ln (e ln x) ] / dx

= d [ ln e + ln (ln x) ] / dx

= d [1 + ln (ln x) ] / dx

= (1/ln x ) . 1/x

= 1 / (x ln x)

does this look correct? (",)...

That is the correct method. Thanks alot!!!! YEAH!