Polynomials- A maths
When 3x^4 + px^3 + qx^2 + 2x-15 is divided by 3x^2 + x-2, the
remainder is x-5. Find the values of constant p and q.
Please help!!
Thxs!
Divide ( 3x^4 + px^3 + qx^2 + 2x - 15 ) by ( 3x^2 + x - 2 )
using long division.
You should get ( x^2 + ((p - 1)/3)x + ((3q - p + 7)/9) ) as the
quotient, and ( ((7p + 5 - 3q)/9)x - ((121 - 6q + 2p)/9) ) as the
remainder.
By comparing coefficients, you will realise that (7p + 5 -
3q)/9 = 1, and (121 - 6q + 2p)/9 = 5
I will let you try working out by yourself ---- p is
7
and q is 15 btw.