1b (i)'s answer should be 4A of current passing through the test
wire. instead of the 9A stated by TIB657M
Reason being: Since it is a series Circuit, there is only one
path in which current can flow. Therefore each resistor in series
has the same amount of current.
using this reason. and taking account that the voltage source
and the standard resistor has not changed. The solution would
be.
step 1 -- Total resistance: 2+1
ohms = 3 ohms
step 2 -- Total current: Emf (12V) divided by
3 ohm = 4A
1b(iI)'s answer should be changed too.
As we know the current passing through the whole circuit =
4A.
The Voltage for the standard resistor is. 4Ax2Ohm = 8V (ohms
law, V= IR)
12V-8V = 4V.
P= VI
4Vx4A = 16W.
Sorry for the mistake though.
So, the correct mass needed is: 24g
By following steps which I just posted.
