Question from H2 Maths Specimen paper

Prove using an algebraic method, that (3x-6)/(x(x+6) cannot lie between 2 certain values (to be determined)

Thanks in advance for your help

ley y be the (3x-6)/(x(x+6)).

so.. 3x-6=xy(x+6)

3x-6=x2y+6xy

x2y+x(6y-3)+6=0

Since there are no values, b2-4ac<o

(6y-3)2-4(y)(6)<0

if u do ur mathematics right u'll get,

1/6<y<3/2