P6 Maths - Q3

kkhing SG

Forbiddensinner SG

Though this is a P6 question, algebra is required.

This question is honestly not Pri standard.

Let breadth of square be x.

Total area of everything = area of all rectangles - area of all squares

(24+x)(36+3x) = 22(6X(6+x)) - 3x^2

Solving this, you will find x.

Area of all squares = 3x^2, so you just need to sub the value of x in.

rurumoo SG

Hiya,

If you look at the length of the BIG rectangle, you can see that it is made up of the lengths of 6 small rectangles. Let's call this length L, shall we? :)

OK, if the BREADTH of the small rectangles are 6cm, we can note that the length of the large rectangle is made up of 3 breadths and 3 lengths. Now, this is the same as 6 lengths.

So, 6L = 3B + 3L

3L = 2L = 18cm

L = 9cm

9cm-6cm = 3cm

3cmx3cm = 9cm square (area of 1 small white square)

9cmx3= 27cm square, which is your answer.

I hope I helped. it was actually fun, lol :D

wAt3v3r SG

I think you made some typo errors.=x

the big rectangle is made up of the length of 5 small rectangles.

so 5L = 3B + 3L

and the following step is

2L = 3B = 18

the rest of the working would be correct. (:

kenn3th SG

Algebra is taught in primary schools now ):

wAt3v3r SG

yes it is, but it is very basic. pri sch students are usually not required so solve qns using algebra.