Anyone can help? :)
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For the reaction A (g) + B (g) <-> C (g) + D (g), suppose
the concentration of these gases were the following equilibrium
mixture:
[A] = 0.5, [B] = 4.0, [C] = 6.0, [D] = 8.0 in a 1 dm3
container.
How many moles of D would have to be added to the mixture to
raise the concentration of A to 1.0 moldm-3?
Option:
A-0.034 mol
B-0.5mol
C-6.04mol
D-12.1mol