Electrolysis

Audi SG

In an electrolysis experiment, the same amount of charge deposited 16g of Cy and 6g of Ti. What was the charge on the titanium ion? +4 is the answer.

Well, how do you solve this? (I did this question before but forgot how to do it now)

Thanks

UltimaOnline SG

Find the no. of mols of electrons transferred.

For every mol of electron accepted per mol of the metal cation, the OS decreases by 1.

Let the OS of Ti cation be X.
Mols of electrons accepted per mol of Ti = 4
Since the OS of Ti metal is 0, hence

X + (-4) = 0
X = +4

yiha093 SG

hey ultima i dun understand where u are going, i can only deduce

16/64= 0.25mol of electron passed through it.

means 0.25mol pass through TI .

then what do i do with that figure ?

qdtimes2 SG

0.5 mol of electron is needed to balance the charge of Cu2+ ion

yiha093 SG

no i still dun understand, can sum1 give a step by step asnwer?

qdtimes2 SG

Cu2+ +2e- = Cu

2 electrons (negative charges) are needed to balance the 2+ positive charge of Cu ion

0.25Cu2+ + 0.5e- = 0.25 Cu

0.125TiX + 0.5e- = 0.125 Ti

TiX + 4e- = Ti

so X = 4+

UltimaOnline SG

qdtimes2’s explanation is correct. Just in case yiha093 is still confused :

yiha093’s error is in the statement, “16/64= 0.25mol of electron passed through it”.

0.25 mol is of Cu(s). Which means 0.5 mol of e- is transferred. Which means 0.125 mol of Ti cations accepts 0.5 mol of e-. Which means each mol of Ti cation accepts 4 mol of e-. Which means initial O.S. of Ti must be +4.

+4 (O.S. of Ti cation) + (4 e-) = 0 (O.S. of metal solid means metal atom means O.S. is zero)

SBS n SMRT SG

for this question, i just remember that ti charge is 4+