Q1.
f(x) = x^3 - 3x^2 + 9x -5
therefore, f'(x) = 3x^2 -6x +9
for all real numbers, for x>0, f'(x) is >0 therefore, the
function f(x) is increasing for all values of x>0..
u can also use graphmatica to check this, to show that the curve
is increasing for all x>0.
Q2.
y=xcosx
therefore,
y' =x(-sinx) + cosx(1)
y' = cosx - xsinx
at x=0.5...
subt and solve for the value
Its usually obvious. for an angle less than 6.28 (2pi), you can
suspect that it requires you to express it in rad. Just base it on
instincts. thats how i do it. Besides, if the range of the graph is
provided, then it also serves as a guide..
eg... the question should go.....
solve for grad tangent for y= xcosx at the point x=0.5 in the
range of eg.. o<x<2pi.
Besides, just think... with the horz axis in degree, 0.5 is
ridiculously small to be considered, therefore, you can outrule deg
mode.