Nathpoop SG How do i solve this two questions. THANKS!(a) e^x(2e^x - 1) = 10 [Ans:0.916] (SOLVED!)(b) log5(8y-6) - log5(y-5) = log4(16), the BOLDED numbers are the base [Ans: 7]
wee_ws SG Hi, For (b): log_5 [(8y - 6)/(y - 5)] = log_4 (4^2) = 2. Then (8y - 6)/(y - 5) = 5^2, from which y can be determined. Thanks!Cheers, Wen Shih
wee_ws SG Hi, Apply a change of base, e.g. log_25 (y) = (log_5 (y)) / (log_5 (25)), so that all terms on LHS follow the same base. Thanks!Cheers, Wen Shih