kittyslut SG 2x^2 - kx = 2 - k, where k is a positive constantneed help in solving this using quadratic formula. thanks.
ThunderFbolt SG Just do as per normal? 2x^2 - kx = 2 - k2x^2 - kx + (k - 2) = 0x = ( k +/- sqrt(k^2 - 8(k-2))/4 = (k-2)/2 or 1
Forbiddensinner SG Just do as per normal? 2x^2 - kx = 2 - k2x^2 - kx + (k - 2) = 0x = ( k +/- sqrt(k^2 - 8(k-2))/4 = (k-2)/2 or 1I think she either forgotten or haven't learn aboutx = [ -b +/- Sq rt (b^2 -4ac) ] / 2a , where a = 2, b = -k, c = k - 2