Hi,
Let u = sqrt(x). Then du/dx = 1 / {2 sqrt(x)} = 1 /
(2u).
Now integral [ 1 / {1 + sqrt(x)} ] dx = integral [ 1 / (1
+ u) ] (2u) du.
=
2 integral [ 1 - 1/(u + 1) ] du.
I believe you should be able to continue from this
point on. Thanks!
Cheers,
Wen Shih