Qn: 93 metal bars are manufactured by one machine. The length, x
in metres, of each of the bars, is recorded.
The results are as follows: ∑x=102.4 and
∑x^2= 329.11
Based on the given question, how do I calculate the Variance and
what does it mean?
The formula I have is
[ ∑ ( x_i - x*)^2] / n
x* = Mean of x. Dunno how to type it.
To simplify the variance formula
first
∑ ( x - x*)^2
Variance = ------------------- where x* is the mean of x
n
∑ ( x^2 - 2xx* + x*^2)
Variance = ----------------------------
n
∑ x^2 - 2x*∑ x + ∑ x*^2
Variance = -------------------------------
n
∑ x^2
∑ x nx*^2
Variance = ------- - 2x*--------- + ---------
n
n
n
∑ x^2
Variance = ------- - x*^2
n
Varaince = [ ∑ x^2 ] /n - [
∑ x /n ] ^ 2
Since ∑x=102.4 , ∑x^2= 329.11, n = 93
Variance = 329.11/93 -
[102.4/93]^2 = 2.33