i dun understand 11bii, and for the venn and graph drawing i jus
cnt do it
For Q. 11(b)(ii), triangle TRW and triangle VSR are similar
triangles, hence you could use this simple and direct method.
For venn diagrams and graph drawings, I am afraid it is a bit
hard to teach you without drawing it out for you to see.
For 11 (a), the graph you drawn is actually y = 1, which is a
straight line through y and parallel to the x-axis. y = x + 1 is a
straight line graph too, but it is a constant increasing graph.
The 1st thing you should do when you deal with this kind of
straight line graph is to find their points on the x-axis and
y-axis.
On the x-axis, y = 0, and on the y-axis, x = 0. In short, you
will have to sub in y = 0 and x = 0 respectively into the original
equation to find the points on the two axis.
In this case, the point on the x-axis will be ( -1 , 0 ) and the
point on the y-axis will be ( 0 , 1 ). Now, draw a straight line
through this two important points, and that line will be y = x +
1.
For 11 (b), it will be slightly tougher, as you will need to
find something called the turning point. For graphs like this which
has x^2 in their equation, it will be a U-shaped or a n-shaped
graph.
It is a good thing that you have find the 3 major points on the
x-axis and y-axis, and the next thing you must do is to find the
turning point. The turning point is also known as the maximum or
the minimum point, depending on the shape and equation of the
graph.
Using differentiation on the equation y = 1 - x^2, you will get
dy/dx = -2x
One thing you must know is that at the turning point, dy/dx =
0.
Hence, -2x = 0, and the turning point is at x = 0.
At x = 0, you will find that y = 1, as shown in your unfinished
graph. With these, you can conclude that y = 1 - x^2 is a n-shaped
graph which passes through the 3 points you marked on the 2 axis,
with ( 0, 1 ) being the maximum point.