A train
travels at 30 km/h and a car travels at a certain uniform speed.
The train left Town A 3 hours before the car, but the car overtook
the train 6 hours after it had set off and arrived at Town
B 2 hours before the train.
(a) What is
the speed of the car?
(b) What is
the distance between the two towns?
A.
Because the
train left Town A 3 hours early at a speed of
30km/ h, we calculate the advantage the train had over the
car.
3 Hours X
30km = 90km advantage
After 6
hour, of driving in the car, the car finally catch up with the
train. So now let see how fast does the car catches up per
hour.
Take
advantage over the time taken
90km / 6
hours = 15 km/ h
Car travel
15km / h faster than train. To get the speed of
the car
15km/ h +
30km/ h =
45 km/h
B.
Speed of the car at 45 km/h.
Speed of the train at 30 km /h.
Car reaches
Town B 2 hours earlier than train.
Train slower
by 60km
Each hour,
car faster by train by 15km /h so I take
60 / 15 = 4
hours
So 4 hours
is the unknown after the car overtook the train to arrived at Town
B.
To find the
distance we take
6 hours
(mentioned) + 4 hours = 10 hours
10 X 45 km/h
=
450 km