A maths - Linear Law

bonkysleuth SG

The diagram below shows part of a straight line graph obtained by plotting 1/y against x. Given that the graph passes through the point (2sq.rt 3, 1) and makes an angle of 30 degrees with the line y =1, express y in terms of x.

Need help with this question.... Thanks !

Mikethm SG

Gradient = tan x where x is the angle made by the line and the x-axis

Therefore, gradient = tan 30 = 1/sqrt(3)

Y= mX+c

At (2sqrt3,1)

1= (1/sqrt3)(2sqrt3)+c

1= 2+c

c= -1

Y= (1/sqrt3)X-1

(1/y)= (1/sqrt3)x-1

Simplify yourself to y.