(a) Vol of Earth removed = Area of trap x length. Answer
in cubic metre.
(b) From the understanding. 1m3 of Earth weights 1.8 x 10^3(
which is1800kg). To find the mass of all soil removed, use the
answer from (a) = xm3 x 1.8 x 10^3.
(c) Calculate % of earth not replace. From understanding, it
means the
(vol of pipe/ vol of trench) x 100%.
Vol of pipe = pi r sq x length.
Then substitute in.
*actually there is a short cut method for the more advance*
(d) Flow = 0.8m/s.
How much water are there in 0.8m of pipe?
pi r sq x 0.8m = vol of water in
0.8m of pipe.
If x amt of water pass through every second. Vol of water pass
through in 1h = ?
How many seconds are there in 1hour?
Multiple the answer you got previously by the amount of seconds
in 1h.
This is my systematic approach.