Here's another question b4 i go sleep:
Susan stands at edge of cliff, throws a ball upwards. The height
of ball above top of cliff in h metres is
h= 8t-5t^2
Q: Susan throws 2nd ball, in exactly same way, 4s after she
throws the 1st .
Find how far apart the 2 balls are, 1s after the 2nd ball is
thrown.
height of 1st ball = 8(5) - 5(5)^2 = 40 - 125 = -85m, meaning it is
85m below cliff.
height of 2nd ball = 8(1) - 5(1)^2 = 8 - 5 = 3m, meaning it is
3m above cliff.
distance apart = 85m + 3m = 88m