Majors oops, sorry, repost again. Cut and paste from my
Words and look what happened.
Anyway, here is my question again.
Need help solving this quadratic. How are the
two equations related? Thanks.
The equation x^2 – 2x + 3 has roots α and
β and the equation x^2 – 4x + p = 0 has
roots
k/α and k/β.
Find the value k and of p.
(Ans k = 6, p = 12)
(x-a)(x-b) = x^2 - (a+b)x + ab = x^2 - 2x + 3
= > a + b = 2 , ab = 3
= > (x-k/a)(x-k/b) = x^2 - ((a+b)k/ab)x + (k^2/ab) = x^2 - 4x
+ p
=x^2 - (2k/3)x + (k^2/3)
= > 2k/3 = 4 = > k = 6
= > p = k^2/3 =
36/3 =
12
Anything else wait for someone else to come, me going out
liao.