ok this question took me about 5+ mins to solve, quite tough...
:(
dot a perpendicular line from G to BE and label it as H
dot a perpendicular line from G to FC and label it as I
Note that by similar triangles,
consider triangles HBG and EBC
because BG = ½BC,
EH = ½BE
HG = ½EC
consider triangles GIC and BFC
because BG = ½BC,
FI = ½FC
GI = ½BF
Thus,
EG² = EH² + HG²
= ¼BE² + ¼EC²
= ¼BC²
GF² = GI² + FI²
= ¼BF² + ¼CF²
= ¼BC²
= EG²
Thus, GF = EG
Since GF = EG, and ED = DF, then GEF is an isosceles triangle
where GD is perpendicular to EF