The equation of the line p is 3y - x = 10.
Find
i) the gradient of the line p
ii) The equation of the line parallel to p and
which passes through the point (6, 10)
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The graph, y = (x+4)(x+1) cuts the x axis at A and the y-axis at
B
Find the coordinates of A and B
I am very bad at Graphs. Could anyone teach me??
i) Rearrange the equation having y as the subject and the
coefficient of x will be your gradient
ii) Using the gradient obtained, sub it into the equation y=mx+c
to find c and you have the equation.
iii) When a curve cuts the x-axis, all the y values are 0 and
when it cuts the y-axis, x is 0. To solve for A and B, its simple
(x+4)=0 and (x+1)=0 since you know that at point A and B the y
value is 0 so solving you can get the x values from there.