Why? Amaths Qns

Nathpoop SG

Why is

lg (x^2y / 1+x) =2

x^2y / 1+x = 2

Therefore, y =100(1+x) / x^2

Can someone help me explain?

Thanks in adv.

Forbiddensinner SG

Why is

lg (x^2y / 1+x) =2

x^2y / 1+x = 2

Therefore, y =100(1+x) / x^2

Can someone help me explain?

Thanks in adv.

There seems to a mistake at the "x^2y / 1+x = 2" part.

The workings should be:

lg ( (x^2)(y)/ 1+x ) = 2

((x^2)(y)/ 1+x ) = 10^2

Hence, y = 100(1+x)/ (x^2)

Only-Way-4-Destiny! SG

Only when both sides are logged then you can remove the logs.

lg (x^2y / 1+x) =2

x^2y / 1+x = 2 (x)

lg ( (x^2)(y)/ 1+x ) = 2

((x^2)(y)/ 1+x ) = 10^2 (correct)

Forbiddensinner SG

Only when both sides are logged then you can remove the logs.

lg (x^2y / 1+x) =2

x^2y / 1+x = 2 (x)

lg ( (x^2)(y)/ 1+x ) = 2

((x^2)(y)/ 1+x ) = 10^2 (correct)

I took quite a bit of shortcut :P

Sorry.