binomial

hey guys.. i keep getting confused over this simple thing... altho simple but gave me lotta problems..

whenever i do binomial, there is this (1/2x)^n-1

how do i expand this?

i always dun know issit [1/(2^n-1.x^n-1)] or [1/(2.x^n-1)]

or issit other answers? teach me please thanks.. i know this looks simple but i really need help on this.. thanks

o i know how to do le... but another question here...

2^n-1 = 5n^-1 solve this.

please help... thanks!

o i know how to do le... but another question here...

2^n-1 = 5n^-1 solve this.

please help... thanks!

Hi,

It's not possible to solve algebraically. Try graphing them. Thanks!

Cheers,
Wen Shih

hey guys.. i keep getting confused over this simple thing... altho simple but gave me lotta problems..

whenever i do binomial, there is this (1/2x)^n-1

how do i expand this?

i always dun know issit [1/(2^n-1.x^n-1)] or [1/(2.x^n-1)]

or issit other answers? teach me please thanks.. i know this looks simple but i really need help on this.. thanks

Hi,

Do you mean (1/2 x)^(n - 1)?

Assuming it is (1/2 x)^(n - 1), it will be simplified to (1/2 x)^ n . (1/2 x)^(-1) by the rule of indices.

Thanks!

Cheers,
Wen Shih

omg thanks so much.. u helped a lot.. thanks