Hi all, can anyone help me with this please?
Qn:
Given that kx³ + 2x² + 2x + 3 and kx³ - 2x + 9 have a common
factor, what are the possible values of k?
Thanks!
hmmm, just noticed that both equations is cube, not square...
guess have to revise the method...
let's imagine (x-Q) is the common factor.
sub x= Q into both equations, and both equations should be equal
to zero, because Q is a factor of both equations...
kQ³ + 2Q² +
2Q + 3 = 0 ----------(1)
kQ³ - 2Q + 9
= 0
----------(2)
equate equation 1 to be equation 2, and find what is Q....
Than sub in Q into either equation to solve for k. So TenSaru is
right!