Hi,
To expand on what eagle has mentioned, you need to use a
suitable substitution.
In (a), let y = sqrt(x). Then dy/dx = 1 / {2sqrt(x)} =
1/2y.
So, integral sin (sqrt(x) dx = integral (sin y) (dx/dy)
dy
= integral (sin y) (2y) dy
Next, we use integration by parts. By the LIATE
classification, sin y is 'T' and y is 'A'. 'A' comes before 'T', so
the rule says that we differentiate sin y and integrate y.
Hope it'll help you to proceed, as these questions are
hard without guiding steps given in the problem statement.
Thanks!
Cheers,
Wen Shih