Sec 3 Emaths

Only-Way-4-Destiny! SG

A rectangular pool can be filled by two pipes together in 6 hours. The smaller pipe alone takes 5 hours longer than the larger pipe to fill the pool. Find them time each pipe will take to fill the pool on its own.

...WTF! Help pls

eagle SG

Question looks very familiar... TYS question is it?

Let the time taken by small pipe alone = Ts
Let the time taken by bigger pipe alone = Tb
Let Volume of pool = V

Rate of flow of small pipe = V/Ts
Rate of flow of bigger pipe = V/Tb

Get the equations out

Ts - Tb = 5
Ts = Tb + 5 ------------- (1)

V / ( V/Ts + V/Tb) = 6
TsTb / (Ts + Tb) = 6
Ts Tb = 6Ts + 6 Tb
Sub (1) in
Tb² + 5Tb = 6Tb + 30 + 6 Tb
Tb² - 7Tb - 30 = 0

Solving, Tb = 10 hours or -3 (reject)
Hence, Ts = 15 hours

Only-Way-4-Destiny! SG

waaaaa! thanks

d3sT1nY SG

...WTF! Help pls

Lol, Relax. It's only February.

eagle SG

Lol, Relax. It's only February.

Should be

Relax, eagle is still around

d3sT1nY SG

Should be

Relax, eagle is still around

Eagle hovering around the forum looking for boys and girls to prey upon.