Need help with a math addition formula

If every month increases by 50, what’s the total at the end of the year?

E.g.
50
100
150
200
250

The cumulative sum will be
50
150
300
500
750

Pain in the brain already.

add every month man, there's only twelve...

Let n be 50?

n + 2n + 3n + 4n + 5n + 6n + 7n + 8n + 9n + 10n + 11n + 12n = 78n

78 x 50 = 3900

I could be wrong ...

Sounds like E maths to me... Number patterns...

This is an Arithmetic Progression

Term n = 50 + (n-1)(50) (a + (n-1)d, where a is first term, d is common difference)

So, the sum of n terms is (n/2)(2a + (n-1)d)
Sum here is (12/2)(100 + 50n - 50) = (50 + 50n)*12

So end of the year, you get 6 * (50 + 50*12) = 3900

Alternatively, you could also find sum of n terms by (n/2)(first term + last term)
first term = 50
last term = 50 * 12 = 600
So, sum = 6* 650 = 3900

Lastly, you could also do what the forumers said above, which is to add up each individual month.