Ok, understood. So that means no heating is required and all?
You simply collect the oxygen gas to separate it from the hydrogen
chloride gas? I always thought when it says REMOVE HCl(g) from O2
means you have to take out the hydrogen chloride gas, leaving
behind the O2 gas. May I know whether it works both ways? Thank
You.
I have a question to pose for everyone here.
Let's say an aqueous solution contains a mixture of the salts
potassium chloride and copper(II) sulphate. to test for presence of
Cl- ions, you add HNO3 followed by Ag(NO)3, resulting in the
formation of a white precipitate(silver chloride in this case). how
do you write the equation for this reaction?
i wrote something like:
HNO3 + Cl- -> HCl + NO3-
HCl + AgNO3 -> AgCl + HNO3
A little confused by this, simply because I do not understand
whether I should include the NO3- ion in the first equation since I
do not know the cation of the salt. What is the purpose of adding
acid, may I ask.
Please do advise.
Cheers!
>>> I always thought when it says REMOVE HCl(g)
from O2 means you have to take out the hydrogen chloride gas,
leaving behind the O2 gas. <<<
That's what I said.
(HCl + O2) - HCl = O2
And to remove HCl, bubble the mixture (of HCl + O2) into water.
Then what's left (in gaseous state), is simply O2.
Why would heating need to be involved?
>>> Let's say an aqueous solution contains a mixture of
the salts potassium chloride and copper(II) sulphate. to test for
presence of Cl- ions, you add HNO3 followed by Ag(NO)3, resulting
in the formation of a white precipitate(silver chloride in this
case). how do you write the equation for this reaction?
<<<
Ag+(aq) + Cl-(aq) --> AgCl(s)
>>> What is the purpose of adding acid, may I ask.
<<<
I've written this question and the solution here on my
"Collection of Chem Qns" thread below.
Find (control-F) "acidify silver nitrate"
http://www.sgforums.com/forums/2297/topics/320107