hi, it's me again! sorry2. i'm having trouble with this
question:
express 5/x-3 +
2x-3/6+x-x^2 - 4/x+2
as a single fraction in its lowest term.
can someone help me teach the steps on how to do this??? thanks
loads.
5 / (x-3) + (2x-3) /
(6+x-x^2) - 4 / (x+2) -->
brackets are important
5 / (x-3) + (2x-3) / (-1)(x^2-x-6) - 4 / (x+2)
5 / (x-3) + (3-2x) / (x-3)(x+2) - 4 / (x+2)
5(x+2) / (x-3)(x+2) + (3-2x) / (x-3)(x+2) - 4(x-3) / (x-3)(x+2)
--> common denominator
(5x + 10 + 3 - 2x - 4x + 12) / (x-3)(x+2) --> combine the
fractions
25 - x / (x-3)(x+2) --> simplify