deteq SG pressure due to liquid column = height x density x gravitational field strength=h/5 x density x gravitational field strength.thus the answer should be A.
iamapebble SG B Height of pressure at X = (4/5)h h -> 100 000 Pa (4/5)h -> 80 000 PaD Apply your formua P = W/t 2W = 3000/t t = 1500s = 25 minutes C Let x be distance between 2 consecutive dots. 60 dots -> 59x. Therefore, 59x -> 1s 10x -> 0.17s (2d.p)
davidche SG guys shld be doing paper 2 nia. the qns and answers requried are longer and those are whats coming out!
symx SG I'm getting my basic right so I can move on to paper 2. Thank guys for the input, I'm very happy that I finally understand how to do it.
