tys e maths ques

last SG · 2008-10-22T14:20:27+00:00

i think ans wrong then.. part (ii) how to do?

eagle SG

ooo... the whole angle outside is the reflex angle, not exterior angle.

yup

for clarity

crucifiedx SG

thanks.. =)

this ques how to do ar?

the two sides of a right-angled triangle are of length 1cm and 2cm respectively, find the two possible values of the third side. Leave your answer in the form square root a, where a is a positive integer.

is the ans 5?

skythewood SG

two possibilties

the unknown is the hypotenuse

or 2 cm is the hypotenuse

crucifiedx SG

two possibilties

the unknown is the hypotenuse

or 2 cm is the hypotenuse

then how to solve..?

eagle SG

thanks.. =)

this ques how to do ar?

is the ans 5?

There are 2 values

1) Consider 2 as the hypotenuse
side will be sqrt(2^2 - 1^2) = sqrt(3)

2) Consider final side as hypotenuse
side will be sqrt (2^2 + 1^2) = sqrt(5)

so a can be 3 or 5

skythewood SG

then how to solve..?

try to solve it. it's something you need to try bah. giving you the answer like that is not really helping you much.

crucifiedx SG

There are 2 values

1) Consider 2 as the hypotenuse
side will be sqrt(2^2 - 1^2) = sqrt(3)

2) Consider final side as hypotenuse
side will be sqrt (2^2 + 1^2) = sqrt(5)

so a can be 3 or 5

i understand le. thanks.

crucifiedx SG

(3-2x)^2 - x(2x-3) = 0

for this ques must i expand everything then factorise or can i just write:

(3-2x)^2=0 or x(2x-3)=0 ?

eagle SG

(3-2x)^2 - x(2x-3) = 0

for this ques must i expand everything then factorise or can i just write:

(3-2x)^2=0 or x(2x-3)=0 ?

Expand is too troublesome

the 2nd one also wrong

Must note that (3-2x)^2 = (2x-3)^2

Then you can factorise 2x-3 out and solve...

crucifiedx SG

Expand is too troublesome

the 2nd one also wrong

Must note that (3-2x)^2 = (2x-3)^2

Then you can factorise 2x-3 out and solve...

(3-2x)^2 = (2x-3)^2

huh? why are they the same?

eagle SG

(3-2x)^2 = (2x-3)^2

huh? why are they the same?

First, you must know that (3-2x) = (-1)(2x-3)

(3-2x)^2 = (3-2x)(3-2x)
= (-1) (2x-3) (-1) (2x-3)
= (2x-3)^2

crucifiedx SG

First, you must know that (3-2x) = (-1)(2x-3)

(3-2x)^2 = (3-2x)(3-2x)
= (-1) (2x-3) (-1) (2x-3)
= (2x-3)^2

don't understand.. =X

eagle SG

which part dun understand?

crucifiedx SG

which part dun understand?

tml then ask u ba.. =)

crucifiedx SG

i forgot how to do this type of ques..

5t^2 = 12t

crucifiedx SG

and how do i factorise

y^2 - 6xy + 5x^2 ?

eagle SG

i forgot how to do this type of ques..

5t^2 = 12t

5t^2 - 12t = 0
t(5t - 12) = 0

eagle SG

and how do i factorise

y^2 - 6xy + 5x^2 ?

y -5x | -5xy
y -x | -xy

so you get (y-5x)(y-x)

tmr I teach u 1 more short cut magic eye method for these type questions

crucifiedx SG

ok. thanks.. =)

so is it like that:

t(5t - 12) = 0

t=0

or 5t-12=0

5t=12

t=12/5 ?

eagle SG

correct!

you are one step closer to your A :D

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