this is for radian approximation...
1 ==> 1+p
is my way of saying as 1 approaches 1+p,
than the next line explains what happens to tan(2x + 1)
when this approximation happens.
if this is out of your syllabus, than just skip this thingie
bah.
the tys answers required you to differentiate first.
Ill give you the solution cos i cant understand what the sol.
means here it is:
x=1
8x= p
dydx = 2 (sec (2x+1))^2
= 3 (sec 3) ^2
8y = 2 (sec 3)^2 * p
= 2.04p
care to xplain? thanks