Use your pig brain and think. This is my thread, u should
be the one getting lost.
Ans to part
1:
By Euler's rule: re^(ix) = rcos x + i rsin x
1 = 1 e^(i 2nx) where x = pie.
When there is no restriction to the argument,
1 = 1e^0 = 1 e^-x = 1 e^x = .....
Therefore, 1 + 1 = 1e^x + 1e^-x which is not equal to 2. In
general, 1 + 1 is not equal to 2.
For 1 +1 = 2, the argument of the complex number 1 has to be
restricted to the principal argument -pie < x <= pie. In
this case, 1e^0 is the actual value we have being using in real
life.
thread starter big fuck?
anyone who dare say e ^ (-x) = 1..... not very smart. use a
calculator and calculate that.
than you will tell me have to include this part "When there is no restriction to the
argument," hey, suddenly, new rules.
you can make your assumptions, i can make mine. get lost.