hmmm... long time since I did solid body...
Still think the 2nd try for Q A is correct leh... Not necessary
must use all value I think. Because v^2/r doesn't give you a =>
The discs are still accelerating... not just rotating at a constant
speed.
Anyway, Q B
Linear acc component perpendicular to B is 235 mm/s^2 sin 32 =
124.53 mm/s^2
We need to find the centre of rotation. So 124.53 / 0.2312 =
538.6 mm from B (in the direction of A for the angular direction as
shown)
So A is 538.6 - 371 = 167.6 mm from the centre of rotation.
Magnitude of acceleration at A = 0.2312 * 167.6 = 38.75
mm/s^2
